Pembahasan Soal Ikatan Kimia

Hello everyone! Today we are going to dive into a step-by-step tutorial on Chemical Bonding, also known as Ikatan Kimia, by solving some common multiple-choice questions.

Let's look at Question 1. An element with atomic number 9 will form an ionic bond with an element with a specific atomic number. Step 1 is checking the configuration of element 9, which is 2 comma 7. With 7 valence electrons, it needs 1 more to be stable, making it a non-metal. Remember, an ionic bond requires a metal and a non-metal, so we need to find a metal element!

In Step 2, let's check the options. Option A is 17, which is 2, 8, 7, a non-metal. Option B is 19, which is 2, 8, 8, 1. This element loses one electron easily, making it a metal. Options C and D are both non-metals. Therefore, the metal in option B is our match. The correct answer is B, 19.

Now for Question 2. Element Z has an electron configuration of 2, 8, 8, 2. We need to identify the compound it forms. In Step 1, we identify the ion. Since Z has 2 valence electrons, it will lose those two electrons to become stable, forming a Z 2 plus cation.

Step 2 is finding the matching compound. We need a valid formula using the Z 2 plus cation. Option A, H Z 2, is incorrect. Option B, Z 2 S O 4, is also wrong because Z 2 plus and S O 4 2 minus would form Z S O 4. In option E, Z 2 plus combines with two F minus ions to correctly form Z F 2. So, the correct answer is E.

By analyzing electron configurations and identifying metal or non-metal properties, you can easily determine bond types and chemical formulas. Great job today, and keep practicing your chemistry skills!