Soal Cerita: Perbandingan Usia

Hello everyone! Today we are solving a quantitative logic problem about the ages of three peers and their parents. Let's look at the question and the relationships provided.

First, we find the ages for Adi's family. Since his father retires this year, A subscript F equals sixty. His father is three times his age, so three A equals sixty, which means Adi is twenty. Because they are peers, Adi, Beti, and Yunus are all twenty years old.

Next, let's look at Beti's family. Her mother's age, B subscript M, is three times Beti's age, or sixty. Since the mother is three years younger than the father, B subscript F minus three equals B subscript M, meaning Beti's father is sixty-three years old.

Now for Yunus's family. Three years ago, the ratio of Yunus to his father matched Adi's current ratio. This gives us Y minus three over Y subscript F minus three equals A over A subscript F. Substituting the values, we get seventeen over Y subscript F minus three equals one third. Solving this, Yunus's father is fifty-four.

Now we evaluate the choices. Our summary shows the children are twenty, while the fathers' ages are sixty, sixty-three, and fifty-four. Checking option B, the order from youngest to oldest is Yunus at fifty-four, Adi at sixty, and Beti at sixty-three. This makes option B the correct statement!

By carefully translating each clue into a mathematical equation, we can solve complex age problems efficiently. Great work on following this logic through to the end. See you in the next lesson!